Помогите решить... Срочно! ​

1) (1/4)^x >= 64 = 2^-2x >= 2^6 = -2x >= 6 = x <= - 3

2) (3/10)^3x-1 < (3/10)^2 = 3x - 1 >2 = 3x > 2 + 1 = 3x > 3 = x > 1

3) -

4) -

5) 8 * (0,5^x)^2 - 17 * 0,5 + 2 <= 0 = 8t^2 - 17t + 2 <= 0 = t Е [1/8,2] = X Е [-1, 3]