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svetka1574

Ответ:

Объяснение:

1) Mr(Na2O2) = 23*2+16*2 =78

W(Na) = Ar(Na) *n / Mr(Na2O2)  *100% = 23*2 / 78  *100% =59%

W(O) = Ar(O) *n / Mr(Na2O2)  *100% = 16*2 / 78  *100% = 41%

2)  Mr(Fe2(CO3)3) = 56*2 + 12*3 + 16*9 =292

W(Fe) = Ar(Fe) *n / Mr(Fe2(CO3)3)  *100% = 56*2 / 292  *100% =38%

W(C) = Ar(C) *n / Mr(Fe2(CO3)3)  *100% = 12*3 / 292  *100% = 12%

W(O) = Ar(O) * n / Mr(Fe2(CO3)3)   *100% = 16*9 / 292  *100% =50%

3) Mr(AlCl3) = 27 + 35,5*3 = 133,5

W(Al) = Ar(Al) *n / Mr(AlCl3)  *100% = 27*1 / 133,5  *100% = 20%

W(Cl) = Ar(Cl) *n / Mr(AlCl3)  *100% = 35,5*3 / 133,5  *100% = 80%

4) Mr(Pb(OH)2 = 207 + 16*2 + 1*2 =241

W(Pb) = Ar(Pb) * n / Mr(Pb(OH)2)  *100% = 207 *1 / 241  *100% =86%

W(O) = Ar(O) *n / Mr(Pb(OH)2)  *100% = 16*2 / 241  *100% =13%

W(H) = Ar(H) * n / Mr(Pb(OH)2)  *100% = 1*2 / 241  *100% =1%

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