Автор - qewewrt

решите систему уравнений методом подстановки​

Ответ

Автор - Itroller

Ответ:

1) x_{1}=-3; y_{1}=6; x_{2}=2;y_{2}=1;\2)x_{1}=2; y_{1}=-1; x_{2}=-3; y_{2}=-6

Объяснение:

1)left { {{x^2-y=3} atop {x+y=3}} right.left { {{x^2-y=3} atop {x=3-y}} right.left { {{(3-y)^2-y=3} atop {x=3-y}} right.left { {{9-6y+y^2-y=3} atop {x=3-y}} right.left { {{y^2-7y+6=0} atop {x=3-y}} right.\\ y^2-7y+6=0\\D=b^2-4ac=49-24=25=5^2\\y_{1}=frac{7+5}{2}=6\\y_{2}=frac{7-5}{2}=1\\left { {{y_{1}=6} atop {x_{1}=-3}} right. left { {{y_{2}=1} atop {x_{2}=2}} right.

2)left { {{x^2+y=3} atop {y-x+3=0}} right. left { {{x^2+y=3} atop {x=3+y}} right.left { {{(3+y)^2+y=3} atop {x=3+y}} right.left { {{9+6y+y^2+y=3} atop {x=3+y}} right.left { {{y^2+7y+6=0} atop {x=3+y}} right.\\ y^2+7y+6=0\\D=b^2-4ac=49-24=25=5^2\\y_{1}=frac{-7+5}{2}=-1\\y_{2}=frac{-7-5}{2}=-6\\left { {{y_{1}=-1} atop {x_{1}=2}} right. left { {{y_{2}=-6} atop {x_{2}=-3}} right.

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