Вычислить. Тригонометрия.
Даю много баллов! Хэлп)

[cos105⁰(cos277⁰sin172⁰-cos7⁰sin82⁰]/(2√2)⁻²=
=(2√2)²·cos105⁰·[1/2(sin(172⁰-277⁰)+sin(172⁰+277⁰))-1/2(sin(82⁰-7⁰)+sin(82⁰+7⁰))]=
=4·2·1/2·cos105⁰·(sin(-105⁰)+sin449⁰-sin75⁰-sin89⁰)=
=4·cos105⁰·(-sin105⁰+sin(2π+89⁰)-sin75⁰-sin89⁰)=
=-4·cos105⁰·sin105⁰-4·cos105⁰·sin75⁰=
=-2·sin210⁰-4·1/2·(sin(75⁰-105⁰)+sin(75⁰+105⁰)=
=-2sin(π+30⁰)-2[(sin(-30⁰)+sin180⁰)]=
=-2(-sin30⁰)-2[(-sin30⁰)+0]=2sin30⁰+2sin30⁰=4sin30⁰=4·(1/2)=2