Ответ Автор - takushnir 6x-²y-¹+(3y-¹-x-²)²= 6/x²y¹+(3/y-1/x²)²=6/x²y+((3х²-у)/(x²у))²=(6x²y-6x²y+х⁴+9у²)/(x⁴у²)=(х⁴+9у²)/(x⁴у²)