Автор - Суворов Антон

Вычислите: 1) 2 + 1/(1+2/[1+1/3]); 2) (2 - ([1/2-1/4]/2)) /(2 + ([1/2-1/4]/2)); 3) 1/(2 - 1/[2 - 1/(2 - 1/3)]).

Ответ

Автор - Воронцова Дарья

1) 2 + 1/(1+2/[1+1/3])=2 + 1/(1+2/[4/3])=2 + 1/(1+3/2)=2 + 1/(5/2)=2 + 2/5=2 2/5; n
2) (2 - ([1/2-1/4]/2)) /(2 + ([1/2-1/4]/2))=(2 - ([1/2]/2)) /(2 + ([3/4]/2))=(2 - 1/4) /(2 + 3/8)=n
1 3/4 : 2 3/8=7/4 * 8/19=7/1 * 2/19=14/19; n
3) 1/(2 - 1/[2 - 1/(2 - 1/3)])=1/(2 - 1/[2 - 1/(5/3)])=1/(2 - 1/[2 - 3/5])=1/(2 - 1/[7/5])=n
1/(2 - 5/7)=1 : 9/7 = 7/9.

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