Автор - Федотов Степан
1) 1 - 2/(3+1/2)=1 - 2/(3 1/2)=1 - 2/1 : 7/2=1 - 2/1 * 2/7=1 - 4/7=3/7; n
2) (8 - 1/(1/2-1/3)) / (8 + 1/(1/2-1/3))=(8 - 1/(1/6)) / (8 + 1/(1/6))=(8 - 6) / (8 + 6/5)=n
2 / (9 1/5)=2/1 * 5/46=1/1=5/23; n
3) 1/(1 + 1/[1 + 1/(1 + 1/2)])=1/(1 + 1/[1 + 1/(3/2)])=1/(1 + 1/[1 + 2/3])=1/(1 + 1/[5/3])=n
1/(1 + 3/5)=1/(1 3/5)=1/ (8/5)=5/8.