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Автор - muter27

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Ответ

Автор - bel72777

Объяснение:

(7а-3b)/(21ab^2) -(7b-2a)/(14a^2 •b)=(7a-3b)/(3•7ab^2) -(7b-2a)/(2•7a^2 •b)=(2a(7a-3b)-3b(7b-2a))/(42a^2 •b^2)=(14a^2 -6ab-21b^2 +6ab)/(42a^2 •b^2)=(14a^2 -21b^2)/(42a^2 •b^2)=7(2a^2 -3b^2)/(7(6a^2 •b^2)=(2a^2 -3b^2)/(6a^2 •b^2)

(6у^2 +1)/(2у) -3у-1=(6у^2 +1-2у(3у+1))/(2у)=(6у^2 +1-6у^2 -2у)/(2у)=(1-2у)/(2у)

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