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Автор - kuponr

Ответ:

Пошаговое объяснение:

$frac{2-2sqrt{2}+sqrt{3}-sqrt{5} -sqrt{6} +sqrt{10}}{2+sqrt{3}-sqrt{5}}$ =

= $frac{(2+sqrt{3}-sqrt{5})-(2sqrt{2} +sqrt{6} -sqrt{10})}{2+sqrt{3}-sqrt{5}}$ =

= $frac{(2+sqrt{3}-sqrt{5})-sqrt{2} (2 +sqrt{3} -sqrt{5})}{2+sqrt{3}-sqrt{5}}$ =

= $frac{(2+sqrt{3}-sqrt{5})(1-sqrt{2})}{2+sqrt{3}-sqrt{5}}$ =

= $1-sqrt{2}$

$15sqrt{1.04} -frac{3}{4} sqrt{5frac{5}{9} } +6sqrt{frac{1}{18}}-(5sqrt{0.02}-sqrt{300})$ =

= $sqrt{225*1.04} -frac{1}{4} sqrt{frac{50*9}{9} } +2sqrt{frac{9}{18}}-sqrt{25*0.02}+10sqrt{3}$ =

= $sqrt{234} -frac{5}{4} sqrt{2} +sqrt{frac{36}{18}}-sqrt{0.5}+10sqrt{3}$ =

= $3sqrt{26} -frac{5}{4} sqrt{2} +sqrt{2}-frac{1}{2} sqrt{2}+10sqrt{3}$ =

= $3sqrt{26} -frac{3}{4} sqrt{2}+10sqrt{3}$

$frac{(sqrt{2} +sqrt{3})(2-sqrt{6} +sqrt{7})-sqrt{21}}{sqrt{7}-1}$ =

= $frac{(sqrt{2} +sqrt{3})(2-sqrt{2}sqrt{3}+sqrt{7})-sqrt{3}sqrt{7} }{sqrt{7}-1}$ =

= $frac{2sqrt{2}-2sqrt{3}+sqrt{2}sqrt{7}+2sqrt{3}-3sqrt{2}+sqrt{3}sqrt{7}-sqrt{3}sqrt{7}}{sqrt{7}-1}$ =

= $frac{2sqrt{2}+sqrt{2}sqrt{7}-3sqrt{2}}{sqrt{7}-1}$ =

= $frac{sqrt{2}sqrt{7}-sqrt{2}}{sqrt{7}-1}$ =

= $frac{sqrt{2}(sqrt{7}-1)}{sqrt{7}-1}=sqrt{2}$

Автор - takushnir

Ответ: во вложении Пошаговое объяснение: