Автор - mosesxu50159

Решение уравнения...​

Ответ

Автор - eqxzert

Ответ:

а) log_{1/125}25 = 0.2x+1

-2/3 = 0.2x+1

-5/3 = 1/5x

x = -25/3

x = -8 1/3

б) log_{1/7} (2x+5) - log_{1/7} 6 = log_{1/7} 2

log_{1/7} (1/3x+5/6) = log_{1/7} 2

1/3x+5/6 = 2

1/3x = 7/6

x = 21/6

x = 3 3/6

в) √(x² - 6) = √(-5x)

x² - 6 = -5x

x² + 5x - 6 = 0

(x+6)(x-1)=0

x_{1} = -6

x_{2} = 1

г) 2sin(x)+1 = 0

2sin(x) = -1

sin(x) = -1/2

x = arcsin(-1/2)

x_{1} = -30°; x_{2} = -150°

либо в радианах

x_{1} = -pi/6; x_{2} = -5pi/6

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