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Проверено экспертом

Автор - hote

1)

displaystyle  lim_{x to  0} frac{4x+sinx}{x-cosx}=frac{4*0+sin0}{0-cos0}=frac{0+0}{0-1}=0

2)

displaystyle  lim_{x to infty} frac{-3x^3+x+1}{3x^3+x^2+1}= lim_{x to infty} frac{x^3(-3+frac{1}{x^2}+frac{1}{x^3})}{x^3(3+frac{1}{x}+frac{1}{x^3})}= lim_{x to infty} frac{-3+0+0}{3+0+0}=-1

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