помогите
Логарифмическое уравнение
log23 (2x-1) - log23 x = 0
2 log 5 x + 5 log 5 x + 2 = 0
log2 (3x - 6) = log2 (2x-3)

log23 (2x-1) - log23 x = 0
{2x-1>0⇒x>0,5
{x>0
x∈(0,5;∞)
log(23)(2x-1)=log(23)x
2x-1=x
2x-x=1
x=1

2 log 5 x + 5 log 5 x + 2 = 0
x>0
7log(5)x=-2
log(5)x=-2/7


log2 (3x - 6) = log2 (2x-3)
{3x-6>0⇒x>2
{2x-3>0⇒x>1,5
x∈(2;∞)
3x-6=2x-3
3x-2x=6-3
x=3