Автор - vikavikavikabi

Помогите решить уравнения
1 - 2y + 3y ^{2}  = y ^{2}  - 2y + 1
(x - 1)(x + 1) = 2(x ^{2}  - 3)
18 - (x - 5)(x - 4) =  - x ^{2}
8 класс срочно зарание спасибо​

Ответ

Автор - matemaster69

1)

1 - 2y + 3 {y}^{2}  =  {y}^{2}  - 2y + 1 \ 2 {y}^{2}  = 0 \ y = 0

2)

(x - 1)(x + 1) = 2( {x}^{2}  - 3) \  {x}^{2}  - 1 = 2 {x}^{2}  - 6 \  {x}^{2}  = 5 \ x =  sqrt{5}

3)

18 - (x - 5)(x - 4) =  -  {x}^{2}  \ 18 -  {x}^{2}  + 9x - 20 =  -  {x}^{2}  \ 9x = 2 \ x =  frac{2}{9}

вот это точно

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