помогите пожалуйста!!!!

f(x) = (4x - 3)(x + 2) = 4x² + 8x - 3x - 6 = 4x² + 5x - 6

f'(x) = 4(x²)' + 5(x)' - 6' = 8x + 5

g(x) = x(2x - 3) = 2x² - 3x

g'(x)= 2(x²)' - 3(x)' = 4x - 3

8x + 5 = 4x - 3

8x - 4x = - 3 - 5

4x = - 8

x = - 2