Автор - 4852088

8x^2 (x-4)-(2x-3)(4x^2+6x+9)-17 при x=0.5

Ответ

Автор - helenbir
8х^2(x-4)-(2x-3)(4x^2+6x+9)-17=8x^3-32x^2-(8x^3+12x^2+18x-12x^2-18x-27)-17=
=8x^3-32x^2-8x^3-12x^2-18x+12x^2+18x+27-17=10-32x^2=
=10-32*(0.5)^2=10-8=2

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