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Автор - teterev

Участок молекулы ДНК имеющий длину 25,5 НМ, содержит 20 адениловых нуклеотидов. Сколько в этом участке  цитидиловых нуклеотидов???

Ответ

Автор - Lar468
25,5: 0,34=75 нуклеотидов всего    А=Т   Т+20    75-40=35  (Ц+Т)   Ц=32,5   Г=32,5

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