Автор - vladinaliza

2c(3c+4)-3c(2c+1)
3a(2a-1)-2a(4+3a)
(b+c)(b-c)-b(b-2c)

Ответ

Автор - Kubanec
2с(3с+4)-3с(2с+1)=6с²+8с-6с²-3с=8с-3с=5с
3а(2а-1)-2а(4+3а)=6а²-3а-8а-6а²=-3а-8а=-11а
(b+c)(b-c)-b(b-2c)=b²-bc+bc-c²-b²-2bc=-c²-2bc

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