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Автор - albinasafronova313

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Ответ

Автор - papagenius

Пошаговое объяснение:

ttdisplaystyle [left({x+frac{{{x^2}-6x}}{{x+1}}*frac{1}{{6-x}}}right)left({frac{{{x^2}+1}}{x}+2} right)=left({x+frac{{x(x-6)}}{{x+1}}*frac{{-1}}{{x-6}}}right)left({frac{{{x^2}+1}}{x}+frac{{2x}}{x}} right) = ]

ttdisplaystyle[=left( {frac{{x(x+1)}}{{x+1}}+frac{{x*(-1)}}{{x+1}}}right)left({frac{{{x^2}+2x+1}}{x}}right)=left( {frac{{x(x+1)-x}}{{x+1}}}right)left({frac{{{{(x+1)}^2}}}{x}}right)=]

ttdisplaystyle [=left({frac{{{x^2}+x-x}}{{x+1}}}right)left({frac{{{{(x+1)}^2}}}{x}}right)=left({frac{{{x^2}}}{{x+1}}}right)left({frac{{{{(x+1)}^2}}}{x}}right)=frac{{{x^2}*{{(x+1)}^2}}}{{(x+1)*x}}=\=x(x+1)]

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