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Ответ

Ответ дан
Nullpo201

ax²+bx+c = 0

D = b²-4ac

x = (-b±✓D)/2a

Ответ

Ответ дан
Amigo3

Ответ: для уравнения а*х>2+ь*х+с=0 корни х1=(-ь+корень из Д) /(2*а), х2=(-ь-корень из Д) /(2*а), где Д=ь^2-4*а*с.

Объяснение:

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