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Автор - KimMinPac

какой обьем кислорода необходим для сжигания 100л пропана

Ответ

Автор - RASSPUTIN

1C3H8 + 5O2 → 3CO2 + 4H2O

100 / 1 = X / 5

X = 100 × 5 / 1 = 500 л

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