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Ответ

Ответ дан
woin123451

x^2-3y=0

y=2x-3

Подставим:

X^2-3(2x-3)=0

x^2-6x+9=0

D=(-6)^2-4*9=36-36=0

Значит, корень один

x=3

Подставим полученный x в y=2x-3

y=2*3-3=3

Ответ: (3;3)

Объяснение:

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