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Ответ

Ответ дан
denisstretyakov

displaystyle tt frac{x^2+x-6}{x^2-x-2}=0 : : : : | : xne-1,:xne2\\ displaystyle tt frac{x^2+3x-2x-6}{x^2+x-2x-2}=0\\ displaystyle tt frac{x(x+3)-2(x+3)}{x(x+1)-2(x+1)}=0\\displaystyle tt frac{(x+3)(x-2)}{(x+1)(x-2)}=0\\displaystyle tt frac{x+3}{x+1}=0\\displaystyle tt x+3=0\\displaystyle tt boxed{bold{x=-3}}

Ответ

Ответ дан
drakerton

Ответ:

-3

Объяснение:

frac{x^2 + x - 6}{x^2-x-2} = 0\\frac{(x+3)(x-2)}{(x+1)(x-2)} = 0\\frac{x+3}{x+1} = 0\\ x neq -1 \\x + 3 = 0\\x = -3

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