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svetka1574

Ответ:

Объяснение:

    400 г                                  Х л

  2C2H6     +      7O2    =      4CO2    +    6H2O

n=2 моль                              n=4 моль

М=30 г/моль                     Vm=22,4 л/моль

m=60 г                                 V = 89,6 л

400 г  С2Н6   -   Х л   СО2

60 г     С2Н6  -  89,6 л  СО2

V(CO2) = 400 * 89,6 / 60= 597 л

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