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svetka1574

Ответ:

Объяснение:

                                  6,72 л              Х моль

    2Mg         +           O2          =     2MgO

                             n=1 моль             n=2 моль

                          Vm=22,4 л/моль

                          V = 22,4 л

6,72 л   О2   -   Х моль  MgO

22,4 л   О2   -   2 моль   MgO

n(MgO) = 6,72 * 2 / 22,4 = 0,6 моль

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