Автор - ILOVEYOU99

решите
1) 8х⁶у³ - 12х³у³ =
2)3b² + a²b + 5ab² + 4a²b - 5ab² - 3b² =
3) (t² + 8t - 9) - (t² - 11t + 10) = 18t - 20 (уравнение)
4) -0.8c(c + 5) - 0.7(10c+5) + 0.8c² + 10c - 4 =
5) 3a + 3a² - b - ab =
6) 3x(x - 2) - (3x - 1)(x + 4) ≥ 8(2 -x) (уравнение)
7) (125 * 5³ - 25 * 5³) / (5 * 5²) - (25 * 5² - 2 * 5²) / 5 =

Ответ

Автор - elizarovapolina
1)4 x^{3} * y^{3} *(2 x^{3} -3)
2)5 a^{2} *b
3)t=-1
4)-(7.5+c)
5)(3a-b)(1+a)
6) xleq  2frac{2}{9}
7)-111

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