Автор - Nurzhan94

Помогите решить cos^215*cos^2 75

Ответ

Автор - nikebod313

cos^{2}15^{circ} cdot cos^{2}75^{circ} = (cos 15^{circ} cdot cos 75^{circ})^{2} = left(dfrac{1}{2} left(cos (15^{circ} -75^{circ}) + cos(15^{circ} + 75^{circ}) right) right)^{2} =\= left(dfrac{1}{2}(cos 60^{circ} + cos 90^{circ})  right)^{2} = left(dfrac{1}{2}left(dfrac{1}{2}  + 0 right)  right)^{2} = left(dfrac{1}{4} right)^{2} = dfrac{1}{16}

Ответ: dfrac{1}{16}

Воспользуйтесь формулами:

a^{n} cdot b^{n} = (ab)^{n}

cos alpha cos beta = dfrac{1}{2} (cos(alpha - beta ) + cos (alpha + beta ))

cos alpha = cos (-alpha) — функция косинус четная.

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