search points attachment profile arrow left arrow right star heart verified symbols equation arrow-down question mark check menu accountancyadministrationagriculturalalgebraallarabicartart_musicbelarusbelarus_altbiologybusinesscatalachemistrychineseeconomicsegzamenglishentrepreneurshipenvironmentethicseuskarafirst_aidfrenchgalegogeographygeologygeometrygermangrammarhealthhistoryindia_langindonesian_langinformaticsitalianjapanesekazachkazach_altkoreanlanguagelatinlawlife_scienceliteraturelogicmathematicsmusicnigerian_langother_languagesotherspedagogicsphilosophyphysical_educationphysicspoliticspsychologyreligionrpa_langrussianrussian_altsciencesecurityskillssocial_sciencesociologyspanishstatisticstechnologytourismtrafficukrainianukrainian_altukrainian_literaturewos_civilisation accountancyadministrationagriculturalalgebraall_1arabicartart_music_2belarusbelarus_altbiologybusiness_2catalachemistry_1chineseeconomicsexam_3englishentrepreneurshipenvironment_2ethicseuskarasecurity_1frenchgalegogeography_4geology_4geometrygermangrammarhealthhistoryindia-langindonesian-langinformaticsitalianjapanesekazachAsset 230koreanlanguagelatinlawlife-scienceliteraturelogic_2mathematicsmusicnigerian-langotherlanguagesother_1pedagogicsphilosophyphysical_educationphysicspoliticspsychologyreligion_1rpa-langrussianrussian_altsciencesecurity_3_mskills_1allsocial_science_5_msociologyspanishstatisticstechnologytourismtrafficukrainianukrainian_altukrainian_literaturewos_civilisation

Ответ

Ответ дан
UluanaV

Ответ:

-1

Объяснение:

sqrt{sin^25-2sin5*sinfrac{11pi }{6}+sin^2frac{11pi }{6} }-sqrt{sin^2frac{5pi }{6}-2sinfrac{5pi }{6}*sin5+sin^25}

Под радикалами используем формулу квадрата разности

(a-b)^2=a^2-2ab+b^2

sqrt{(sin5-sinfrac{11pi }{6})^2}-sqrt{(sinfrac{5pi }{6}-sin5)^2}

Пользуемся формулой: sqrt{a^2}=|a|

|sin5-sinfrac{11pi }{6} |-|sinfrac{5pi }{6}-sin5 |=|sin5-sin(pi +frac{5pi }{6})|-|sinfrac{5pi }{6}-sin5 |=\ \ =|sin5+sinfrac{5pi }{6}|-|sinfrac{5pi }{6}-sin5|=|sin5+frac{1}{2}|-|frac{1}{2}-sin5|

При раскрытии модуля учитываем, что

sin5+frac{1}{2}<0; frac{1}{2}-sin5>0

|sin5+frac{1}{2}|-|frac{1}{2}-sin5|=-(sin5+frac{1}{2})-(frac{1}{2}-sin5)=\ \ -sin5-frac{1}{2}-frac{1}{2}+sin5=-1

Ответ

Ответ дан
takushnir

Ответ: во вложении Объяснение:

Ответы и объяснения

Не тот ответ, который тебе нужен?