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asenysh250103

Ответ:

Пошаговое объяснение:

BE=EC=3

BA=12 т.к катет противолежащий углу 30 гр. равен половине гипотенузы

ВN=NA=6

CA^2=BA^2-BC^2=144-36=108

CA=sqrt{108}=6sqrt{3}

CM=3sqrt{3}

EM=sqrt{9+27} =sqrt{36} =6

EN=sqrt{36-9} =sqrt{27} =3sqrt{3}

NM=sqrt{36-27} =sqrt{9} =3\

P=6+3+3sqrt{3}=9+3sqrt{3}

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