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Автор - Ton1k

Найти объем правильной треугольной призмы, если сторона = 20 см., А высота = 9 см.

Ответ

Автор - MM18
V = Sосн * h
Sосн = 1/2 a^2 * sin60 = 1/2 * 20^2 * √3/2 = 400√3/4 = 100√3
V = 100√3 * 9 = 900√3

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