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avakyanchanel

frac{x^2}{x^2-9} =frac{12-x}{x^2-9} (ODZ: xneq -3; xneq 3)\x^2=12-x\x^2-12+x=0\x^2+4x-3x-12=0\x(x+4)-3(x+4)=0\(x+4)(x-3)=0\x_{1} neq -4\x_{2} =3              frac{6}{x-2} +frac{5}{x} =3 (ODZ: xneq 2; xneq 0\frac{6}{x-2} +frac{5}{x} -3=0\frac{6x+5x-10-3x^2+6x}{x(x-2)} =0\17x-10-3x^2=0\-3x^2+17x-10=0\3x^2-2x-15x+10=0\x(3x-2)-5(3x-2)=0\(3x-2)(x-5)=0\x_{1} =frac{2}{3} ; x_{2} =5

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