Автор - OpenOffice

49 ^log(7)4
Log(2)log(5) 8√5
Log(√2)log(1/3) 1/9
Log(12)3+log(12)4
7 ^[2log(7)16]
10[^1-1g5]
4^[3-log(4)64]
6^[2/log(5)6]

Ответ

Автор - yanaaleksandrov
49^loq(7)4=(7^2)^loq(7)4=(7^loq(7)4)^2=4^2=16
loq(V2)loq(1/3)1/9=loq(V2)2=2loq(2)2=2
loq*(12)3+loq(12)4=loq(12)(3*4)=loq(12)12=1
7^[2loq(7)16]=((7^loq(7)16)^2)=16^2=256
10^[1-lq5]=10^1/10^lq5=10/5=2
4^[3-loq(4)64]=4^3/4^loq(4)64=4^3/4^3=1
6^[2/loq(5)6]=6^[(loq(5)25)/(loq(5)6)]=6^[loq(6)25)]=25
второй пример
loq(2)(loq(5)5^(1/8))=loq(2)1/8=loq(2)2^(-3)=-3

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