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Автор - GokuSsj4

Среднее квадратичное трёх чисел a, b и c вычисляется по формуле q=√ (a2+b2+c2)/3. Найдите среднее квадратичное чисел 3,4 и √23

Ответ

Автор - Бориссс

Ответ:


4


Пошаговое объяснение:


q=√((a^2+b^2+c^2)/3)       a=3;b=4, c=√23


√(3²+4²+(√23)²)/3)=√((9+16+23)/3)=√(48/3)=√16=4

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