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Автор - Veronika757

избавьтесь от иррациональности в знаменателе дроби
 frac{6}{2- sqrt[3]{2} }

Ответ

Автор - m11m
   6     =      6(2² + 2 ∛2 + ∛(2²))        =  6 (4 +2 ∛2 + ∛4) =
2 -∛2      (2 -∛2)(2² +2 ∛2 +∛2²)               2³ - (∛2)³

= 6 (4+2 ∛2  + ∛4) =   4+ 2 ∛2 + ∛4
          8 - 2 

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