Задание 150 (а)
Решите пожалуйста по действиям

   [(2m+1)/(2m-1) - (2m-1)/(2m+1)] / (4m/(10m-5)) =
= [(2m+1)² - (2m-1)²]×(10m-5) / (4m(2m-1)(2m+1)) =
= [(2m+1-2m+1)(2m+1+2m-1)×(10m-5) / (4m(2m-1)(2m+1)) =
= (2×4m×(10m-5)) / (4m(2m-1)(2m+1)) =
= 10(2m-1) / (2m-1)(2m+1) =
= 10 / 2m+1