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Автор - кара17

Как решить 4 x в квадрате минус икс равно нулю

Ответ

Автор - krugly1981
4x² - x = 0
D = b² - 4ac = (-1)² - 4 × 4 ×0= 1
x1 = ( 1 + 1) / 8 = 2/8 = 0,25
x2 = ( 1 - 1) / 8 = 0

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