Автор - Nurzhan94

найдите а19 и n-й член арифметической прогрессий

Ответ

Проверено экспертом

Автор - Universalka

1) a₁ = 0,5      a₂ = - 1

a₂ = a₁ + d

d = a₂ - a₁ = - 1 - 0,5 = - 1,5

a₁₉ = a₁ + 18d = 0,5 + 18 * (- 1,5) = 0,5 - 27 = - 26,5

a₁₉ = - 26,5

aₙ = a₁ + d(n - 1)

aₙ = 0,5 - 1,5(n - 1) = 0,5 - 1,5n + 1,5 = 2 - 1,5n

aₙ = 2 - 1,5n

2) a₁ = 13       a₂ = 7

a₂ = a₁ + d

d = a₂ - a₁ = 7 - 13 = - 6

a₁₉ = a₁ + 18d = 13 + 18 * (- 6) = 13 - 108 = - 95

a₁₉ = - 95

aₙ = a₁ + d(n - 1) = 13 - 6(n - 1) = 13 - 6n + 6 = 19 - 6n

aₙ = 19 - 6n

3) a₁ = - 3,3          a₂ = - 1,2

a₂ = a₁ + d

d = a₂ - a₁ = -1,2 + 3,3 = 2,1

a₁₉ = a₁ + 18d = - 3,3 + 18 * 2,1 = - 3,3 + 37,8 = 34,5

a₁₉ = 34,5

aₙ = a₁ + d(n - 1) = - 3,3 + 2,1(n - 1) = - 3,3 + 2,1n - 2,1 = 2,1n - 5,4

aₙ = 2,1n - 5,4

4) a₁ = 2        a₂ = 14

a₂ = a₁ + d

d = a₂ - a₁ = 14 - 2 = 12

a₁₉ = a₁ + 18d = 2 + 18 * 12 = 2 + 216 = 218

a₁₉ = 218

aₙ = a₁ + d(n - 1) = 2 + 12(n - 1) = 2 + 12n - 12 = 12n - 10

aₙ = 12n - 10

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