Ответ Проверено экспертом Автор - kirichekov lim ((sin²(x/2))/x²)=lim((sin(x/2))/x)²=(lim(sin(x/2))/(2x/2))²=x->0 x->0 x->0=(lim(1/2*(sin(x/2))/(x/2))²=(1/2*lim(sin(x/2))/(x/2))²=1/4*1=1/4=0,25 x->0 x->0