Автор - bukiagio3
(z-8)(z+8)/(z+3) * 1/z(z+8) - (z+8)/z(z-3)= (z-8)/z(z+3) - (z+8)/z(z-3)= ((z-8)*(z-3)-(z+3)(z+8))/z(z+3)(z-3)= (z²-11z+24-z²-11z-24)/z(z+3)(z-3)= -11/z²-9
Ответ:
-22/(z²-9)
Объяснение:
(z²-64)/(z+3) ·1/(z²+8z) -(z+8)/(z²-3z)=(z-8)(z+8)/(z+3) ·1/(z(z+8)) -(z+8)/(z(z-3))=(z-8)/(z(z+3)) -(z+8)/(z(z-3))=((z-8)(z-3)-(z+8)(z+3))/(z(z+3)(z-3))=(z²-3z-8z+24-z²-3z-8z-24)/(z(z+3)(z-3))=-22z/(z(z+3)(z-3))=-22/((z+3)(z-3))=-22/(z²-9)