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Автор - astapenkonik

Найдите координаты точек пересечения графиков функции y=-4x^ и y=3x-1

Ответ

Автор - veronika0306
-4х²=3х-1
4х²+3х-1=0
D=9-4×4(-1)=25
х1,2=-3+-5/8=
х1=-1, х2=0.25
у1=3×(-1)-1=-4 у2=(-4)×(0.25)²=-0.25
(-1;-4) и (0.25;-0.25)

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