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Автор - colorsit548

Какую массу оксида ртути (II) необходимо использовать для получения 50,4
л кислорода, если доля выхода продукта реакции составляет 75%?

Ответ

Автор - maria7017
2HgO=2Hg+O2
nпрак(O2)=50,4/22,4=2,25моль
nтеор(O2)=2,25/0,75=3моль
n(HgO)=6моль
m(HgO)=1302г

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