Автор - Anton751

y= корень(1-sinxcosx), x0= pi 4

Ответ

Проверено экспертом

Автор - oganesbagoyan
y(x) =√(1-sinx/cosx) , xo =π/4.
y(xo) =  y(π/4)=√(1-sin(π/4)/cos(π/4))  =√(1 - (1/√2)/(1/√2)) =√(1 - 1) = 0 .

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