Автор - LesynovSlava

Решите логарифмические неравенства ДАЮ 65 БАЛЛОВ:
1)log_{0,5} (2-5x) leq -2
2)log_2 (4-3x) leq -3
3)lod_4 (3-4x) geq -1
4)log_{0,2} (15-2x) geq -2\
5)log_{0,8} (3-5x) geq 0

Ответ

Автор - igundane

1)log_{0,5}(2-5x)leq -2\x<frac{2}{5} \2-5xgeq 0,5^{-2}<=>2-5xgeq 4<=>-5xgeq 2=>xleq -frac{2}{5}\2)log_2(4-3x) leq-3\x<frac{4}{3}\4-3xleq 2^{-3}<=>4-3xleq frac{1}{8}<=>-3xleqfrac{31}{8} =>xgeq frac{31}{24} \frac{31}{24}leq x <frac{4}{3} \3)log_4(3-4x )geq -1\x<frac{3}{4} \3-4xgeq 4^{-1}<=>3-4xgeq frac{1}{4} <=>-4xgeq -frac{11}{4} =>xleq frac{11}{16}\4)log_{0,2}(15-2x)geq-2\x<frac{15}{2}\12-2xleq 0,2^{-2}<=>15-2xleq 25<=>-2xleq 10=>xgeq -5\-5leq x<frac{15}{2}

5)log_{0,8}(3-5x)geq 0\x<frac{3}{5} \3-5xleq 0,8^0<=>3-5xleq 1<=>-5xleq -2=>xgeq frac{2}{5}\frac{2}{5} leq x<frac{3}{5}

Ответ

Автор - tamarabernukho

Ответ:

Пошаговое объяснение:

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