Автор - zxalima30

cos^2 x=sinx-1 help mee​

Ответ

Автор - daniilzhulanov

displaystyle cos^2(x)=sin(x)-1\1-sin^2(x)-sin(x)+1=0\sin^2(x)+sin(x)-2=0\D=1+8=9\sin(x)=dfrac{-1+3}{2}=1\x=dfrac{pi}{2}+2pi k, kinmathbb Z\sin(x)=dfrac{-1-3}{2}=-2\xinvarnothing

Ответ

Автор - Mirage86

I hope this helps you

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