Автор - zxalima30

sin x/2 +cosx=1 help plizzz​

Ответ

Автор - nikebod313

sin dfrac{x}{2} + cos x = 1\\sin dfrac{x}{2} + cos x - 1 = 0\\sin dfrac{x}{2} +2sin^{2}dfrac{x}{2} = 0\\sin dfrac{x}{2} bigg(1 + 2sin dfrac{x}{2} bigg) = 0

left[begin{array}{ccc}sin dfrac{x}{2} = 0        \ 1 + 2sin dfrac{x}{2} = 0 end{array}right

left[begin{array}{ccc}sin dfrac{x}{2} = 0     \ \ sin dfrac{x}{2} = -dfrac{1}{2}  end{array}right

left[begin{array}{ccc}dfrac{x}{2} = pi n,  n in Z                       \ \dfrac{x}{2} = (-1)^{k} bigg(-dfrac{pi}{6} bigg) + pi k,  k in Z end{array}right\\\left[begin{array}{ccc}x = 2pi n,  n in Z                  \ x = (-1)^{k+1} dfrac{pi}{3} + 2 pi k,  k in Z end{array}right

Ответ: x = 2pi n,  n in Z, x = (-1)^{k+1} dfrac{pi}{3} + 2 pi k,  k in Z

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