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Автор - ДжулияК

Решите неравенство f'(x)>0, если f(x)=-x^2-4x-2006.

Ответ

Автор - Elrigo
f`(x)= -2x - 4 + 0 = -2x - 4;

 -2x - 4 > 0
-2x > 4
2x < -4
x < -2

x∈(-∞; -2)

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