Автор - Zooooom987

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Ответ

Автор - aastap7775

sqrt{6+x-x^2} = 1 - x <=> left { {{1-xgeq 0} atop {6+x-x^2 = (1-x)^2}} right. \\1 - x geq 0 => x leq 1;\6+x-x^2 = x^2 - 2x + 1 => 2x^2 -3x - 5 = 0 => x_1 = -1, x_2 = 2.5 => x = -1\Answer: x = -1

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