Автор - Konstantinovna123

Найдите cosA если sinA 9/41 и П/2

Ответ

Автор - svetazuna


sin²A + cos²A = 1  ⇒  cosA = √1 - sin²A;

при sinA = 9/41:   cosA = √1 - (9/41)² = √1 - 81/1681 = √1681/1681 - 81/1681 = √1600/1681 = 40/41;

при sinA = П/2:   cosA = √1 - (1)² = √1 - 1 = √0 = 0

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