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Ответ

Ответ дан
Бориссс

Ответ:

a=pm1.5

Объяснение:

Один из корней уравнения x^2-4ax+8=0 на 2 больше другого. Найдите а.

по теореме Виета

x₁*x₂=8

x₁+x₂=4a             ⇒      x₂=x₁+2

displaystyle\left { {{x_1(x_1+2)=8} atop {x_1+(x_1+2)=4a}} right. \\\left { {{x_1^2+2x_1=8} atop {2x_1+2=4a}} right.\\\ left { {{x_1^2+2x_1=8} atop {x_1=2a-1}} right.\\\(2a-1)^2+2(2a-1)=8\\4a^2-4a+1+4a-2-8=0\\4a^2=9\\a^2=frac{9}{4}\\a=pmfrac{3}{2} \\Otvet:a=pm1.5

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