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Автор - 343839

Внешнее сопротивление 5 Ом, Сила тока 0,2 А, ЭДС 2 В. Найдите силу тока короткого замыкания.

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Проверено экспертом

Автор - larisaorlova65
Закон Ома: I=ε/(R+r).При коротком замыкании сила тока:I к.з. =ε/r,
Iк.з. =2В/ 5 Ом=0,4 А

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