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Автор - DavyJo

log0.3(2x-4)>log0.3(x+1)

Ответ

Проверено экспертом

Автор - Rechnung
log_{0,3}(2x-4) textgreater  log_{0,3}(x+1)\\ left { {{2x-4 textgreater  0} atop {x+1 textgreater  0}} right.\\ left { {{2x textgreater  4} atop {x textgreater  -1}} right.\\ left { {{x textgreater  2} atop {x textgreater  -1}} right.= textgreater   x textgreater  2\\0 textless  0,3 textless  1\\2x-4 textless  x+1\2x-x textless  1+4\x textless  5\\xin(2;5)

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